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x is chosen at random from the set {1,2,3,4} and y is chosen at random from the set {5,7,9}.
Quantity A
The probability that xy will be even
Quantity B
The probability that (x+y) will be even
  • a)
    Quantity A is greater.
  • b)
    Quantity B is greater.
  • c)
    The two quantities are equal.
  • d)
    The relationship cannot be determined from the information given.
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
x is chosen at random from the set {1,2,3,4} and y is chosen at random...
Given:
  • x is chosen from the set {1,2,3,4}
  • y is chosen from the set {5,7,9}
We have to compare 'the probability that the product of x & y will be even' and 'the probability that the sum of x & y will be even.'
The probability that xy will be even

For the product of two positive integers to be even, at least of them must be even. We see that the set 2 consists of only odd integers, and there are two terms (2 and 4) in the set 1 and are even. Thus, if we choose one of those two terms (2 and 4), (x × y) would be even. In other way, the selection from the set 2 does not matter.
# of ways the product of x and y is even
= (# of ways to choose an even integer from the set 1) × (# of ways to choose any integer from the set 2)

These 6 ways would be
  • 2 × 5 = 10 (even)
  • 2 × 7 = 14 (even)
  • 2 × 9 = 18 (even)
  • 4 × 5 = 20 (even)
  • 4 × 7 = 28 (even)
  • 4 × 9 = 36 (even)
Total # of ways x and y can be chosen = C1× C1= 4 × 3 = 12 ways
The probability that xy will be even 

Now let's calculate the probability that (x + y) will be even
The probability that (x + y) will be even

The sum of two positive integers would be even if either both are even or both are odd. As we see that the set 2 had only odd integers, thus, if we choose odd integers from the set 1, we get the sum of x and y as even.
This situation is similar to the one discussed for Quantity A; for Quantity A, from the set 1, we would choose any of the two even integers out of the four integers, for Quantity B, we would choose any of the two odd integers out of the four integers. Selection from the set 2 does not matter.
Thus, the probability that (x+y) will be even = the probability that xy will be even = 1/2 (result copied from above)
Thus, Quantity A (= 1/2) is equal to Quantity B (= 1/2).
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x is chosen at random from the set {1,2,3,4} and y is chosen at random from the set {5,7,9}.Quantity AThe probability that xy will be evenQuantity BThe probability that (x+y) will be evena)Quantity A is greater.b)Quantity B is greater.c)The two quantities are equal.d)The relationship cannot be determined from the information given.Correct answer is option 'C'. Can you explain this answer?
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